Section+4.5

there are parts where it decreases. ||  || correct || Therefore, if //a// makes the denominator 0 in sec (1/cos) than cos //a// = 0. Finally, in cot (cos/sin), cos //a// is in the numerator which makes the result be 0. ||  || correct - good explanation! ||
 * Student Answers || Student Feedback || Teacher Feedback ||
 * 51. False, since the graph isn't continuous,
 * 52.True, asymtotes apear when the denominator = 0.
 * 53. A, -tan //x// ||  || correct ||
 * 54. E, sin //x// ||  || correct ||